Answer:
[tex]5393.4gH_2O[/tex]
Explanation:
Hello there!
In this case, for the described chemical reaction, we can write:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
Thus, by considering the 1:2 mole ratio of methane to water, and the molar mass of the latter (18.02 g/mol), the following is useful to calculate the mass of water that is produced:
[tex]149.65molCH_4*\frac{2molH_2O}{1molCH_4} *\frac{18.02gH_2O}{1molH_2O}[/tex]
Which is equal to:
[tex]5393.4gH_2O[/tex]
Which is not among the choices.
Regards!
