Given the reaction:
[tex]2HNO_3+Ca(OH)_2\to Ca(NO_3)_2+2H_2O[/tex]We're going to write a net ionic equation for this reaction as follows:
1. First, write the total ionic equation:
[tex]^{}Ca^{2+}_{aq}+2OH^-_{aq}+2H^+_{aq_{}}+2NO^-_3\to^{}Ca^{2+}_{aq}+2NO^-_3+2H_2O[/tex]2. Now, we could cancel the same type of ions that are in both sides of the reaction. Therefore, the net ionic equation is:
[tex]H^+_{aq}+^{}OH^-_{aq}\to H_2O_{(l)}[/tex]