Assume that it takes a college student an average of 5 minutes to find a parking spot in the main parking lot. assume also that this time is normally distributed with a standard deviation of 2 minutes. what percentage of the students will take between 2 and 6 minutes to find a parking spot in the main parking lot?
Therefore probability of finding a spot between 2 and 6 minutes is P(x<6)-P(x<2) =P(Z<0.5)-P(Z<-1.5) =0.6915-0.0668 =0.6247 => More than half of the students (62.5%) finds a space between 2 and 6 minutes.
